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using this information below, find art major: x=46 x/=50 s=5 theatermajor= x=70

ID: 2954046 • Letter: U

Question

using this information below, find art major:                    x=46         x/=50                  s=5 theatermajor=            x=70           x/=75                        s=7 the z score for each student. which performed better within their class? the coefficient of variation for both art and theaterclasses which class was more variable? what would be the range of grades for the art students thatwould cover at least 88.89% of the students? using this information below, find art major:                    x=46         x/=50                  s=5 theatermajor=            x=70           x/=75                        s=7 the z score for each student. which performed better within their class? the coefficient of variation for both art and theaterclasses which class was more variable? what would be the range of grades for the art students thatwould cover at least 88.89% of the students?

Explanation / Answer

1. Since z-score = (x-xbar)/s     zart = (46-50)/5 =-0.8                       ztheater = (70-75)/7 = -0.7143 2. The theater majors score was in a higher percentile and was lessbelow the mean than the art major, so the theater major didbetter. 3. Since Cv = s/xbar, or to express as a percentage,multiply by 100.     Cart = 5/50 =0.1                                Ctheater = 7/75 = .09333 4. Standard deviation and variance are used to determine how largeof a spread there was. Since v = s2 , std. dev. andvariance are both greater for the theater class, meaning it was themore variable of the two. 5. With a normal distribution, half of the data is below the meanand half is above. So, we'll assume the 88.89% is split evenly toboth sides. Therefore, 44.445% will be on each side, with 5.555% ofthe students will lie at the extremes on each side.     To start, we calculate the z-score thatcorresponds to 0.05555, which will give us the negative z-score(the positive one can be obtained by multiplying by -1). Using theinvNorm command, you get z = -1.593268, and the negative of that is1.593268. Using this in the equation for z-score: a) -1.593268 =(x-50)/5              b) 1.593268 = (x-50)/5                            -7.966342 =x-50                       7.966342 = x-50       x =42.033658                                   x = 57.96634 Therefore, range is [42.033658,57.96634].