12. A frequency table for BMISeptember Category and Gender. Underweight Normal O
ID: 2954280 • Letter: 1
Question
12. A frequency table for BMISeptember Category and Gender.
Underweight
Normal
Overweight
Obese
Male
1
26
4
1
Female
5
27
2
1
Afrequency table of BMI April category and gender:
Underweight
Normal
Overweight
Obese
Male
3
22
6
1
Female
2
29
4
0
1. Nowsuppose we select a student at random
a. What isthe probability that the student is normal in September? InApril?
b. Thestudent is a male and normal in April.
c. Thestudent is normal in April given that we have selected a malestudent?
d. Thestudent is normal in April given that we have selected a femalestudent?
2. Are BMI and gender independent in September? InApril? Explain.
Underweight
Normal
Overweight
Obese
Male
1
26
4
1
Female
5
27
2
1
Explanation / Answer
sept p= 53/67= .791 april p = 51/67 = .7611b) p(student male)*p(normal) p(male)= 32/67 (32/67)(.7611)=.3635
c) P(student normal, given male) P(number of normal males/total number of males) = (22/32)=.6875
d) P (number of normal females/total number of females)=.82857
2. independent -> variables dont effecteachother. so probability of being a female doesnt change probability ofbeing normal weight. So False
When you are determining if two events are independent, youare determining if the probability of one happening effects theprobability of the other happening. So if two events areindependent, p(a)p(b)= p(ab) in this problem you want to see if the probability of being amale (or female) effects the probability of having a normal BMI .So to solve this problem, you would do the probability of being amale * probabiliy of being normal weight and see if it equals theprobability of being a male and normal weight. Since they do nothave the same probability, the two events are notindependent.
Related Questions
Navigate
Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.