For a project, I surveyed 40 kids, 20 female and 20 male. Iasked each person if

Question

For a project, I surveyed 40 kids, 20 female and 20 male. Iasked each person if they exercised and how many minutes ofexercise did they do per day? Gender Name Q1: Do You Exercise? Q2: How Many Minutes Do You Exercise? 1 F Ashley Yes 50 2 F Vanessa Yes 60 3 F Erika Yes 35 4 F Jessica No 0 5 F Famel Yes 60 6 F Ashley No 0 7 F Blakely No 0 8 F Bianca Yes 40 9 F Malencia Yes 70 10 F Rachael Yes 35 11 F Kaenesha Yes 90 12 F Crystal No 0 13 F Ferni No 0 14 F Edna Yes 40 15 F Wendy Yes 5 16 F Dawn No 0 17 F Rebecca No 0 18 F Tessica No 0 19 F Nallely Yes 30 20 F Beatriz No 0 21 M Alan No 0 22 M Erik Yes 40 23 M Daniel Yes 80 24 M Alex Yes 90 25 M Leo Yes 60 26 M Julio Yes 60 27 M David Yes 30 28 M John Yes 20 29 M Turner No 0 30 M Michael Yes 30 31 M Juan Yes 30 32 M Jesus Yes 50 33 M Wilfredo No 0 34 M Gerardo Yes 40 35 M Regulo Yes 60 36 M Ruben No 0 37 M Eduardo Yes 60 38 M Gibran Yes 120 39 M Diego Yes 50 40 M Robert Yes 30 a)Calculate twoconfidence intervals, one for the proportion of yeses and one forthe true mean of the numerical responses in the population.Pleaseinclude all steps for creating the confidence intervals. (it would be preferable if a confidence interval can bedisplayed in like a type of graph-ish quality too besidecalculations) For a project, I surveyed 40 kids, 20 female and 20 male. Iasked each person if they exercised and how many minutes ofexercise did they do per day? Gender Name Q1: Do You Exercise? Q2: How Many Minutes Do You Exercise? 1 F Ashley Yes 50 2 F Vanessa Yes 60 3 F Erika Yes 35 4 F Jessica No 0 5 F Famel Yes 60 6 F Ashley No 0 7 F Blakely No 0 8 F Bianca Yes 40 9 F Malencia Yes 70 10 F Rachael Yes 35 11 F Kaenesha Yes 90 12 F Crystal No 0 13 F Ferni No 0 14 F Edna Yes 40 15 F Wendy Yes 5 16 F Dawn No 0 17 F Rebecca No 0 18 F Tessica No 0 19 F Nallely Yes 30 20 F Beatriz No 0 21 M Alan No 0 22 M Erik Yes 40 23 M Daniel Yes 80 24 M Alex Yes 90 25 M Leo Yes 60 26 M Julio Yes 60 27 M David Yes 30 28 M John Yes 20 29 M Turner No 0 30 M Michael Yes 30 31 M Juan Yes 30 32 M Jesus Yes 50 33 M Wilfredo No 0 34 M Gerardo Yes 40 35 M Regulo Yes 60 36 M Ruben No 0 37 M Eduardo Yes 60 38 M Gibran Yes 120 39 M Diego Yes 50 40 M Robert Yes 30 Ashley Ashley Ashley Ashley Ashley Ashley Ashley Ashley Ashley Ashley a)Calculate twoconfidence intervals, one for the proportion of yeses and one forthe true mean of the numerical responses in the population.Pleaseinclude all steps for creating the confidence intervals. (it would be preferable if a confidence interval can bedisplayed in like a type of graph-ish quality too besidecalculations) (it would be preferable if a confidence interval can bedisplayed in like a type of graph-ish quality too besidecalculations) Gender Name Q1: Do You Exercise? Q2: How Many Minutes Do You Exercise? 1 F Ashley Yes 50 2 F Vanessa Yes 60 3 F Erika Yes 35 4 F Jessica No 0 5 F Famel Yes 60 6 F Ashley No 0 7 F Blakely No 0 8 F Bianca Yes 40 9 F Malencia Yes 70 10 F Rachael Yes 35 11 F Kaenesha Yes 90 12 F Crystal No 0 13 F Ferni No 0 14 F Edna Yes 40 15 F Wendy Yes 5 16 F Dawn No 0 17 F Rebecca No 0 18 F Tessica No 0 19 F Nallely Yes 30 20 F Beatriz No 0 21 M Alan No 0 22 M Erik Yes 40 23 M Daniel Yes 80 24 M Alex Yes 90 25 M Leo Yes 60 26 M Julio Yes 60 27 M David Yes 30 28 M John Yes 20 29 M Turner No 0 30 M Michael Yes 30 31 M Juan Yes 30 32 M Jesus Yes 50 33 M Wilfredo No 0 34 M Gerardo Yes 40 35 M Regulo Yes 60 36 M Ruben No 0 37 M Eduardo Yes 60 38 M Gibran Yes 120 39 M Diego Yes 50 40 M Robert Yes 30

Explanation / Answer

Since the mean and the variance of the whole population arenot known before hand you need to estimate both the mean and thevariance. let yes = 1 and no = 0 Above is a kind of mapping we will use to estimate confidenceinterval for the mean In such a scenario the estimated mean for the number of yes =27 / 40 Also as the degree of freedom in this case for estimation ofvariance = total number of samples - 1 the 1 is subtracted to account for mean estimation hence degrees of freedom = 39 estimate of standard deviation = 27/40 The confidence interval of mean 27/40 is 27/40 -39*27/40 to 27/40 + 39*27/40

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