When crossing two types of seeds, it is expected that you getfour types of seeds

Question

When crossing two types of seeds, it is expected that you getfour types of seeds in the ratio of 7:4:3:2. In a sample of 800 seeds, 360 were of the first type, 220 ofthe second type, 150 of the third type and 70 of the fourthtype. Does this sample fit the proposed distribution? Use the .05 level. When crossing two types of seeds, it is expected that you getfour types of seeds in the ratio of 7:4:3:2. In a sample of 800 seeds, 360 were of the first type, 220 ofthe second type, 150 of the third type and 70 of the fourthtype. Does this sample fit the proposed distribution? Use the .05 level.

Explanation / Answer

run a vhi-square test for goodness of fit H0:The seeds fit the ratio of 7:4:3:2 HA:The seeds do not fit the ratio of 7:4:3:2 expected ocurences: (divide the number of the type (like 7 forthe first type of seed) by 16, then multiply by 800. Forexample...(7/16)(800)=350 expectd for first type. 350 of first type 200 of seconds type 150 of third type 100 of fourth type df=n-1=4 chi-square=(observed-expected)2/expected calculator's chi-square-value: 11.286 p-value=.0235 Because p is less than , we can rejectthe null hypothesis and conclude that the seeds do not fit the7:4:3:2 ratio.

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