Assume that hte average amount spent per month for long-distancecalls through th

Question

Assume that hte average amount spent per month for long-distancecalls through the long-distance carrier is $38.25, and that thestandard deviation is $11.75. If a sample of 100 customers isselected, the mean amount spent per month for long distance callsof this sample belongs to a sampling distribution.
a.) what is the shape of this sampling distribution?
b.) what is the mean of this sampling distribution?
c.) what is the standard deviation of this samplingdistribution?

a.) what is the shape of this sampling distribution?
b.) what is the mean of this sampling distribution?
c.) what is the standard deviation of this samplingdistribution?

Explanation / Answer

Given =38.25, s=11.75, n=100 (a) normal distribution (b) mena= =38.25 (c) standard deviation = s/n = 11.75/sqrt(100) = 1.175

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