A baseball team has schedules its opening game for April 1. If it rains on April

Question

A baseball team has schedules its opening game for April 1. If it rains on April 1, the game is postponed and will be played on the next day if it does not rain. The team purchases insurance against rain. The policy will pay 1000 for each day, upto 2 days, that the opening game is postponed. The insurance company determines the number of consecutive days of rain beginning on April 1 is a Poisson random variable with a mean 0.6. What is the standard deviation of the amount that the insurance company will have to pay?

Explanation / Answer

Hint: The insurance company determines the number of consecutivedays of rain beginning on April 1 is a Poisson random variable witha mean of 0.6 =0.6, X~Pois() So, the mean and variance of Poisson distribution is the same,so the variance is equal to mean = 0.6 The standard deviation of the amount that the insurancecompany will have to pay is =var =0.6 =0.77.

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