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a) Refrigerator sales - The number ofrefrigerators sold per day at a local appli

ID: 2955278 • Letter: A

Question

a)   Refrigerator sales - The number ofrefrigerators sold per day at a local appliance store is shown inthe table, along with the corresponding probabilities. Findthe mean, variance and standard deviation                #of Refrigerators                  SoldX                  0         1         2          3           4                  Probability P(X)      0.1      0.2      0.3       0.2        0.2 b) Number of Bedrooms - A recent survey byan insurance company showed the following probabilities for thenumber of bedrooms in each insured home. Find the Mean,Variance and Standard Deviation for the distribution.             #of bedroomsX             2               3            4            5             ProbabilityP(X)            0.3             0.4         0.2         0.1 c)   Job Bids  -   A landscapecontractor bids on jobs where he can make $3000 profit. Theprobabilities of getting one, two, three, or four jobs per monthare shown.                #ofjobs                  1                     2                  3               4              Probability               0.2                  0.3                0.4            0.1 d) A lottery offers one $1000 prize, one $500 prize andfive $100 prizes. One thousand tickets are sold at $3each. Find the expectation if a person buys twotickets. Assume that the player's ticket is replaced aftereach draw and that the same ticket can win more than oneprize. a)   Refrigerator sales - The number ofrefrigerators sold per day at a local appliance store is shown inthe table, along with the corresponding probabilities. Findthe mean, variance and standard deviation                #of Refrigerators                  SoldX                  0         1         2          3           4                  Probability P(X)      0.1      0.2      0.3       0.2        0.2 b) Number of Bedrooms - A recent survey byan insurance company showed the following probabilities for thenumber of bedrooms in each insured home. Find the Mean,Variance and Standard Deviation for the distribution.             #of bedroomsX             2               3            4            5             ProbabilityP(X)            0.3             0.4         0.2         0.1 c)   Job Bids  -   A landscapecontractor bids on jobs where he can make $3000 profit. Theprobabilities of getting one, two, three, or four jobs per monthare shown.                #ofjobs                  1                     2                  3               4              Probability               0.2                  0.3                0.4            0.1 d) A lottery offers one $1000 prize, one $500 prize andfive $100 prizes. One thousand tickets are sold at $3each. Find the expectation if a person buys twotickets. Assume that the player's ticket is replaced aftereach draw and that the same ticket can win more than oneprize.              Probability               0.2                  0.3                0.4            0.1 d) A lottery offers one $1000 prize, one $500 prize andfive $100 prizes. One thousand tickets are sold at $3each. Find the expectation if a person buys twotickets. Assume that the player's ticket is replaced aftereach draw and that the same ticket can win more than oneprize.

Explanation / Answer

mean, = XP(X) =2.2
variance, 2 = X2P(X) -2 = 6.4 - 2.22 = 1.56 standard deviation, = 1.249 b) # of bedrooms X 2 3 4 5 Probability P(X) 0.3 0.4 0.2 0.1 XP(X) 0.6 1.2 0.8 0.5 X2P(X) 1.2 3.6 3.2 2.5 mean, = XP(X) =3.1
variance, 2 = X2P(X) -2 = 10.5 - 3.12 =0.89 standard deviation, = 0.94 c) # of jobs X 1 2 3 4 Probability P(X) 0.2 0.3 0.4 0.1 XP(X) 0.2 0.6 1.2 0.4 X2P(X) 0.2 1.2 3.6 1.6 mean, = XP(X) =2.4
variance, 2 = X2P(X) -2 = 6.6 - 2.42 = 0.84 standard deviation, = 0.92 mean, = XP(X) =3.1
variance, 2 = X2P(X) -2 = 10.5 - 3.12 =0.89 standard deviation, = 0.94 c) # of jobs X 1 2 3 4 Probability P(X) 0.2 0.3 0.4 0.1 XP(X) 0.2 0.6 1.2 0.4 X2P(X) 0.2 1.2 3.6 1.6 mean, = XP(X) =2.4
variance, 2 = X2P(X) -2 = 6.6 - 2.42 = 0.84 standard deviation, = 0.92 standard deviation, = 0.92 Sold X 0 1 2 3 4 Probability(X) 0.1 0.2 0.3 0.2 0.2 XP(X) 0 0.2 0.6 0.6 0.8 X2P(X) 0 0.2 1.2 1.8 3.2