I am not sure about my answers and just need some critiquing For a normal distri

Question

I am not sure about my answers and just need some critiquing For a normal distribution, identify the z-score location that would separated the distribution into two sections so that there is a. 70% in the body on the right-hand side     = 0.52 b. 80% in the body on the right hand side     = 0.83 c. 75% in the body on the left hand side       =0.67 d. 90% in the body on the left hand side       =1.28 For a normal distribution, find the z-score values that separate ( This one I am clueless) a. The middle of 60% of the distribution from the 40% in the tails. b. The middle 70% of the distribution from the 30% in the tails c. The middle 80% of the distribution from the 20% in the tails d. The middle 90% of the distribution from the 10% in the tails I am not sure about my answers and just need some critiquing For a normal distribution, identify the z-score location that would separated the distribution into two sections so that there is a. 70% in the body on the right-hand side     = 0.52 b. 80% in the body on the right hand side     = 0.83 c. 75% in the body on the left hand side       =0.67 d. 90% in the body on the left hand side       =1.28 For a normal distribution, find the z-score values that separate ( This one I am clueless) a. The middle of 60% of the distribution from the 40% in the tails. b. The middle 70% of the distribution from the 30% in the tails c. The middle 80% of the distribution from the 20% in the tails d. The middle 90% of the distribution from the 10% in the tails

Explanation / Answer

Note: if the left hand area is less than 0.5, then z should be negative. So some of your signs are off. a. Let the left hand area = 0.30. z = -0.5244
b. Let the left hand area = 0.20. z = -0.8416
c. Let the left hand area = 0.75. z = 0.6745
d. Let the left hand area = 0.90. z = 1.2816

a. Let the left hand area = 0.80. z = -0.8416 to 0.8416
b. Let the left hand area = 0.85. z = -1.036 to 1.036
c. Let the left hand area = 0.90. z = -1.2816 to 1.2816
d. Let the left hand area = 0.95. z = -1.6448 to 1.6448

Hope this helps,
Mike

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