A distributor of sports equipment is considering buying a new synthetic yo-yo st

Question

A distributor of sports equipment is considering buying a new synthetic yo-yo string from a manufacturer who claims that the string has a mean breaking strength of 15 pounds. Test the hypothesis that µ= 15 pounds against the alternative that µ. 15 pounds if a random sample of 50 strings is tested and found to have a mean breaking strength of 14.8 pounds with a standard deviation of 0.5 pounds.
Use a 0.01 level of significance.

Which is true about the decision?
A. Average breaking strength = 15 B. Computed statistic lies in right tail
C. Fail to reject the null hypothesis D. Type I error is at a = .005
E. Average breaking strength . 15

Explanation / Answer

It's unclear from the question whether this is supposed to be a one or two tailed test. The test statistic is t= (14.8-15)/0.5/sqrt 50= -2.76. (Degrees of freedom 49) Consulting a T table this is significant at the .01 level on either a one or two tailed test, so i guess it doesn't really matter. D is the answer that makes sense.

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