There are seven parts in a factory bin. Four of the parts are in condition blue.

Question

There are seven parts in a factory bin. Four of the parts are in condition blue. Two parts are in condition yellow. The other part is condition red.
The condition of the part cannot be determined by touching it, scanning it with the naked eye, sniffing it, listening to it, picking it up, or by any other form of casual observation.
Three machines will be made from the seven parts, each machine requiring two parts. There will be one part left unused.
To make the machines, parts will be randomly and sequentially selected from the bin. As soon as two parts are selected , they are combined into a machine before any other parts are selected. Thus, the first machine produced will be made from the first two parts selected. And so forth. A machine will perform best and last longest if its two parts have the same conditions. For example, both blue.
A machine made out of a blue and a yellow part will not last as long as one whose parts have matching conditions.
A machine with a red part will not last as long or perform as well as one without a red part.
A. Calculate the probability that the first machine made will have two parts in condition blue.
B. Calculate the probability that the first machine made will have two parts in condition yellow
C. Calculate the probability that none of the three machines will have a part in condition red.

Explanation / Answer

a 4/7*3/6=2/7 b 2/7*1/7=2/49 c-probability of not selecting a red in any of 6 attempts. We are drawing parts without replacement. 6!/7!=6/7*5/6*4/5*3/4*2/3*1/2=1/6

Related Questions

Navigate

• Browse (All)
• Browse T
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.