Hi, I need help with this problem Thank you, Todd The probability that a person

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Hi, I need help with this problem
Thank you, Todd
The probability that a person in the United States has type O positive blood is 38%. Three unrelated people in the United States are selected at random.(Source: American Association of Blood Banks)

(a) Find the probability that all three have type O positive blood (b) Find the probability that none of the three have type O positive blood (c) Find the probability that at least one of the three have type O positive blood Please explain your answers Hi, I need help with this problem
Thank you, Todd
The probability that a person in the United States has type O positive blood is 38%. Three unrelated people in the United States are selected at random.(Source: American Association of Blood Banks)

(a) Find the probability that all three have type O positive blood (b) Find the probability that none of the three have type O positive blood (c) Find the probability that at least one of the three have type O positive blood Please explain your answers

Explanation / Answer

a)
The probability that a person in the U.S has type O positive blood is 38%.
The chance of type O positive for one type of person is independent of the chances for the other three persons having type O positive.
P(All 3 have type O postive blood)=(0.38)(0.38)(0.38)
=0.054872.
b) Because the probability that a person has type O positive blood is 0.38, the probability that none of none of the three have type O positive blood is given by, =1-0.38 =0.62. P(none of the three have type O positive blood)=(0.62)(0.62)(0.62) =0.23833. c) The phrase "at least one" means one or more. The complement to the event "at least one is successful" is the event "none are having O positive blood". Using the rule of complements, P(at least 1 of the three is having O positive blood)=1-P(none are having O positive blood) =1-0.23833 =0.7617.

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