<p>From past experience, an Olympic gymnast knows that his scores on the vault f

Question

<p>From past experience, an Olympic gymnast knows that his scores on the vault follow an approximate normal distribution with mean 9.3 and standard deviation 0.4. Each gymnast in a competition must perform two vaults. Assuming the gymnast's scores are independent from one vault to another, what is the probability that his total score for his two vaults at a competition exceeds 19?</p>
<p>A. 0.2061</p>
<p>B. 0.4343</p>
<p>C. 0.3594</p>
<p>D. 0.2389</p>
<p>E. 0.3264</p>
<p>Can I get the detail of the solution, please?</p>

Explanation / Answer

From past experience, an Olympic gymnast knows that his scores on the vault follow an approximate normal distribution with mean 9.3 and standard deviation 0.4. Each gymnast in a competition must perform two vaults. Assuming the gymnast's scores are independent from one vault to another, what is the probability that his total score for his two vaults at a competition exceeds 19?

A. 0.2061

B. 0.4343

C. 0.3594

D. 0.2389

E. 0.3264

Can I get the detail of the solution, please?

z = (19/2-9.3)/sqrt(0.4/2) = 0.4472

llok up in Z table to get P = 0.3274

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