A restaurant critic goes to a place twice. If she has an unsatisfactory experien

Question

A restaurant critic goes to a place twice. If she has an unsatisfactory experience during both visits, she will go once more. Otherwise she will make only the two visits.
Assuming that the results for different visits are independent and that the probability of a satisfactory experience in any visit is .8

a) assign probabilities to each outcome.

b) Find the probabilities of at least two unsatisfactory visits.

c) Find the conditional probability of at least one satisfactory visit given at least one unsatisfactory visit.

Explanation / Answer

Probability of Happy Happy: .8*.8 Probability of one happy/one sad: .8*.2+.2*.8 Probability of going two sads, one happy: .2*.2*.8 Probability of going three sads: .2*.2*.2 So this is the second and third, .2*.2 really. Because the third visit only happens if they are both sads. Well, they're independent, so .8 normally, but: (.8*.2+.2*.8+.2*.2*.8)=successes (.8*.2+.2*.8+.2*.2*.8+.2*.2*.2)=total with condition =0.977777778 Ok, so you had an issue with the third part? Let me explain. There were only 4 possible scenarios as seen at the top. Since we are given that one was not good, we can ignore the first one. Then, we want to find the probability of them enjoying it once, after not once. So Successes are ones where that happens, total is all of them where it was unsatisfactory once. Make sense? Mail if not.

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