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Please post the images of your work. The second image is used for reference for

ID: 2962282 • Letter: P

Question

Please post the images of your work. The second image is used for reference for a few parts in this question.


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l be given. Use Exercise 1(a) to show that every sine coefficient, bn, n = 1,2,..., in the full Fourier series of feven must be zero. (Hint: Recall from calculus that if h(x) is odd, then Use Exercise 1(b) to show that the coefficients an for f even also satisfy (Hint: Recall from calculus that if h(x) is even, then Conclude that the full Fourier series of f even is equivalent to the Fourier cosine series of f. Use Exercise 1(a) to show that every cosine coefficient, an, n = ,1,2,..., in the full Fourier series of f odd must be zero. Use Exercise 1(c) to show that the coefficients bn for f odd also satisfy Conclude that the full Fourier series of f odd is equivalent to the Fourier sine series of f. Show that if f is even and g is odd. then f g is odd. Show that if f and g are even, then f g is even, c Show that if f and g are odd. then f g is even.

Explanation / Answer

[Large extbf{Problem 2a}]

Since (sin) is odd and (f_{ ext{even}}) is even, by Exercise 1(a), the product of those expressions is odd. Thus, by the hint, the integral is zero.

[Large extbf{Problem 2b}]

Since (cos) is even and (f_{ ext{even}}) is even, by Exercise 1(b), the product of those expressions is even. Thus, by the hint given, we have

[a_n = dfrac{1}{ell} int_{-ell}^{ell} f(x)cos(npi x/ell),dx = dfrac{2}{ell} int_0^{ell} f(x)cos(npi x/ell),dx]

[Large extbf{Problem 2c}]

Since (cos) is even and (f_{ ext{odd}}) is odd, by Exercise 1(a), the product of those expressions is odd. Thus, by the hint, the integral is zero.

[Large extbf{Problem 2d}]

Since (sin) is odd and (f_{ ext{odd}}) is odd, by Exercise 1(c), the product of those expressions is even. Thus, by the hint given, we have

[b_n = dfrac{1}{ell} int_{-ell}^{ell} f(x)sin(npi x/ell),dx = dfrac{2}{ell} int_0^{ell} f(x)sin(npi x/ell),dx]

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