1. Suppose a die with six sides (1,2,3,4,5,6) is tossed. (a.) What is the probab
ID: 2965737 • Letter: 1
Question
1. Suppose a die with six sides (1,2,3,4,5,6) is tossed.
(a.) What is the probability that the number that appears is a 5?
(b.) What is the probability that the number that appears is divisible by 2?
(c.) If the die is tossed twice, nd the probability that the sum of the numbers appearing is at least 4.
2. Suppose a fair coin is tossed 3 times.
(a.) Write out all possible outcomes (i.e. HHT, etc).
(b.) What is the probability of obtaining three tails?
(c.) What is the probability of obtaining two heads and one tail?
(d.) What is the probability of no heads?
(e.) What is the probability of obtaining at least 1 head?
3. A bag contains 4 blue marbles, 3 green marbles, 2 white marble and 1 red marble.
(a.) Suppose a marble is selected from the bag and replaced. What is the probability of receiving a
blue marble on the rst selection and a blue marble on the second selection?
(b.) Suppose a marble is selected from the bag and replaced. What is the probability of receiving a
blue marble on the first selection and not a blue marble on the second selection?
(c.) Suppose a marble is selected from the bag and replaced. What is the probability of receiving at
least one blue marble and a white marble (in either order)?
(d.) Suppose a marble is selected from the bag and not replaced. What is the probability of receiving
a blue marble on the rst selection and a blue marble on the second selection?
Explanation / Answer
1.a)5 appears once, hence P=1/6
b)2,4,6. P=1/2
c)total 36 outcome(6*6)
(1,2)(2,1)(1,1) have sum less than 4
Therefore P=33/36=11/12
2)a)HHH,HHT,HTT,TTT,HTH,THT,THH,TTH
b)P=1/8
c)P=3/8
d)no head means all tails i.e. 1. P=1/8
e)at least one head means outcome excluding no head. P=7/8
3)a)P=4/10*4/10
b)P=4/10*6/10
c)P=4/10*2/10+2/10*4/10
d)P=4/10*3/9
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