In order to determine the density of a clay soil, an undisturbed sample was take

Question

In order to determine the density of a clay soil, an undisturbed sample was taken in a sampling tube of 100 mm internal diameter. The length of the sample in the tube was found to be 212 mm. The following data were obtained:

Mass of tube (empty) = 1.820 kg

Mass of tube with clay sample = 5.018 kg

Mass of tube and clay sample after drying = 4.323 kg

Calculate the water content (w), the bulk unit weight () and the dry unit weight (d) of the sample. If the particle specific gravity (Gs) is 2.6, determine the void ratio and the percentage saturation (S) of the clay.

Explanation / Answer

w = 5.018-4.323 = 0.695 kg

() = 5.018-1.820 = 3.198 kg

(d) = w - () = 3.198-0.695 = 2.503 kg

volume of tube = pi*(d2/4)*l = 3.14*(1002/4)*212 = 1664200 mm3 = 1.6642 x 10-3 m3

density of clay = 2.6*1000 = 2600 kg/m3

volume of clay = m/d = 2.503/[2600] = 9.627 x 10-4 m3

void ratio = (16.642 - 9.627)/16.642 = 0.4215

S = (3.198-2.503)/3.198 = 21.73 % saturated by weight

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