i would greatly appreciate any help... A cylinder of unspecified radius r and he
ID: 2969891 • Letter: I
Question
i would greatly appreciate any help...
Explanation / Answer
1) lateral surface(theta,z) = r*theta*z where -pi<theta<pi and 0<z<h
surface area = integral(ds) = integral(r*dtheta*dz) = R*2pi*h
2) integral(xyz) = integral(r*xyz*dtheta*dz) = integral(r^3sin(theta)cos(theta)z*dtheta*dz) = 0 since sin is an odd function so its integral in one period is zero.
4) a) lateral surface(theta,phi) = r^2*sin(theta)*d(theta)*d(phi) where -pi<phi<pi and 0<theta<pi
c) integral(x^2 + y^2 + z^4) = integral({ [r*cos(phi)sin(theta)]^2 + [r*sin(phi)sin(theta)]^2 + [r*cos(theta)]^2} r*sin(theta)*d(theta)*d(phi))
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