Octanitrocubane (ONC) is among the most powerful non-nuclear explosives currentl

Question

Octanitrocubane (ONC) is among the most powerful non-nuclear explosives currently known. It is also notoriously difficult to synthesize. The percent composition of pure octanitrocubane was found to be 20.70% carbon, 24.14% nitrogen and 55.16% oxygen by mass.

Given this information, calculate the empirical formula of octanitrocubane.

The empirical formula of octanitrocubane is C__N__O__. (Enter whole number subscripts…)

If the molecular or molar mass of octanitrocubane is known to be 464.13 g/mol, determine the molecular formula of octanitrocubane using this information combined with your previous answer.

The molecular formula of octanitrocubane is C__N__O__. (Enter whole number subscripts…)

Explanation / Answer

20.70/100 =. 207

24.14/100 = 0.2414

55.16/100 = 0.5516

Now, 0.207:0.2414:0.5516 = 5:6:14

464.13/25 g/mol = 18.5, so molecular formula becomes

18.5 x 5 = 92, 18.5 x6 =111 and 18.5 x 14 =259

So C2N2O5

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