Use |y| = c > 0 if and only if y = + - c to solve the following for x. |x - 8| =

Question

Use |y| = c > 0 if and only if y = + - c to solve the following for x. |x - 8| = 17 |x2 - 8| = 17 |x2 - 8| = 7x |x2 - 8| = 7x - 20 Define, for real numbers a and b, show that Max {a, b} = a + b/2 + |a - b|/2 and Min {a, b} = a + b/2 + |a - b|/2. For each of the equations in (a)-(h), match the solution space over R with appropriate set in (i)-(viii). |x| = Max {x, -2x + 6}

Explanation / Answer

Prove: Max{a,b}=(a+b)/2 +|a-b|/2 if a>b then |a-b|=a-b and Max{a,b)=(a+b)/2 +(a-b)/2=a which is the max if b>a then |a-b|=b-a and Max{a,b)=(a+b)/2 +(b-a)/2=b which is the max .... Prove Min{a,b)=(a+b)/2 -|a-b|/2 if a

Related Questions

Navigate

• Browse (All)
• Browse U
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.