This is a simplified cross-sectional profile of an oil or gas well. This is a co

Question

This is a simplified cross-sectional profile of an oil or gas well. This is a completed and producing well. The well has a vertical section that penetrates overlying bedrock, and a horizontal section that follows the petroleum reservoir. Hydraulic fracturing (fracking) was used to enhance hydrocarbon production from within the reservoir. Understanding the pressure and temperature conditions of a hydrocarbon reservoir are critical in evaluating what kinds of resources the reservoir may contain. These values are measured directly during drilling, but it is helpful to have estimates of them before drilling. This well bottoms out at 6,000 feet beneath the wellhead.

If the geothermal gradient in this area is 80.0°F / mile (increasing downward) and the wellhead temperature is 60°F, what is the predicted temperature in °F at at depth of 6,000 feet? Round your answer to the nearest 10°F.

Select one: a. 80°F b. 4,800°F c. 150°F d. 90°F e. 300°F

WELL HEAD WELL HEAD Cement Conducto 1.000 feet Casing AQUIFER Cement Cement Surface Conductor Casing Casing 2,000 feet Drilling Fluid Cement termediate Casing Surface 3,000 feet casing Drilling Fluid 4,000 feet Intermediate Casing 5,000 feet Target Formatio 6,000 feet Source: http://www.api.org/-/media/Files/Policy Exploration HYDRAULIC FRACT ILLUSTRATION 121609.pdf SOIL AQUIFER

Explanation / Answer

The predicted temperature T =(temperature gradient)(formation depth) + wellhead temperature

temperature gradient = 80oC

formation depth = 6000ft = 1.136364 mi

wellhead temperature = 60oF

T = 80*1.136364+60

= 90.90912 + 60

the temperature at 6000ft is T = 150.90912oF

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