According to a study conducted in 2003, the total number of U.S. jobs that are p

Question

According to a study conducted in 2003, the total number of U.S. jobs that are projected to leave the country by year t, where t = 0 corresponds to 2000, is represented by the following function where N(t) is measured in millions. N(t) = 0.0018425(t + 10)3.5 (0 t 15) How fast was the number of U.S. jobs that are outsourced changing in 2003? How fast will the number of U.S. jobs that are outsourced be changing at the beginning of 2011 (t = 11)? (Round your answers to the nearest whole number.) 2003 jobs/year 2011 jobs/year

Explanation / Answer

First, the formula is not typed correctly. If the "4.5" at the end of it really is a factor, as written, then it would have got included in the coefficient at the front:

0.0018425(t+8)4.5 = 0.00829125(t+8)

If it was supposed to be an exponent:
0.0018425(t+8)^4.5
it would give ridiculous results, yielding, for the number, n, ofjobslost in 2015,
n = 10^6 * N = 1842.5(23^4.5) = 2.478*10^9

Second, the number of jobs lost per year is a rate of job loss. Differentiating it would give an acceleration of the job-loss rate, which would be expressed, not in jobs/year, but in jobs/year/year = jobs/year^2.

Please clarify and/or correct your question.

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