MATHEMATICAL METHODS IN ELECTRICAL ENGINEERING QUESTION PLEASE SHOW ALL WORK!!!!

Question

MATHEMATICAL METHODS IN ELECTRICAL ENGINEERING QUESTION PLEASE SHOW ALL WORK!!!!!!!!!!!!!

MATHEMATICAL METHODS IN ELECTRICAL ENGINEERING QUESTION PLEASE SHOW ALL WORK!!!!!!!!!!!!! 4. The augmented matrix below represents a linear system of equations. Solve for the variables using any tool you choose (computer, calculator, Matlab). Full point for correct answer; no points for partial credit. If it has no solution, or no unique solution, please 5 0 3 2 4 -27 2 4 0 1 1 10 9 9 -3 2 1 60 2 1 16 3 4 -79 0 6 5 8 1 37 state that.

Explanation / Answer

Solving the system of equations by Gaussian Elimination

%naiv_gauss.m---------------------------------------------------------------------------------------------------------

function x = naiv_gauss(A,b)
n = length(b); x = zeros(n,1);
for k=1:n-1 % forward elimination
for i=k+1:n
xmult = A(i,k)/A(k,k);
for j=k+1:n
A(i,j) = A(i,j)-xmult*A(k,j);
end
b(i) = b(i)-xmult*b(k);
end
end
% back substitution
x(n) = b(n)/A(n,n);
for i=n-1:-1:1
sum = b(i);
for j=i+1:n
sum = sum-A(i,j)*x(j);
end
x(i) = sum/A(i,i);
end
end

---------------------------------------------------------------------------------------------------------------------------------

%gauss.m--------------------------------------------------------------------------------------------------------------------

A = [5 0 3 2 4;2 4 0 1 1;9 9 -3 2 1;2 1 16 3 4;0 6 5 8 1];
b =[-27;10;60;-79;37];
X= naiv_gauss(A,b)

------------------------------------------------------------------------------------------------------------------------------

Output:

X =

3.0000
2.0000
-4.0000
7.0000
-11.0000

--------------------------------------------------------------------------------------------------------------------------------

So the solution is X matrix.

Related Questions

Navigate

• Browse (All)
• Browse M
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.