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An electrical substation has two busbars that are aligned parallel to each other

ID: 2990354 • Letter: A

Question

An electrical substation has two busbars that are aligned parallel to each other and located 0.8 meters apart. At a particular instant, one busbar is carrying 1.9 kA and the other busbar is carrying (0.5)* 1.9 kA in the other direction (i.e., it has a phase offset of 120 degrees). Assuming that the current in the first busbar creates a magnetic field of strength B=? I1 / 2?r Teslas, the air around the busbars has a permeability of ?=?0=4 ?10-7 H/m, and the force per unit length experienced by the second busbar is determined by F=? I1 I2 / 2?r, determine the force per unit length felt by the second busbar in N/m:

An electrical substation has two busbars that are aligned parallel to each other and located 0.8 meters apart. At a particular instant, one busbar is carrying 1.9 kA and the other busbar is carrying (0.5)* 1.9 kA in the other direction (i.e., it has a phase offset of 120 degrees). Assuming that the current in the first busbar creates a magnetic field of strength B=? I1 / 2?r Teslas, the air around the busbars has a permeability of ?=?0=4 ?½10-7 H/m, and the force per unit length experienced by the second busbar is determined by F=? I1 I2 / 2?r, determine the force per unit length felt by the second busbar in N/m:

Explanation / Answer

force between two parallel wires is given by F = u0i1i2L/2pid

where u0 = constnat = 4pi*10^-7 H/m,

i1, i2 are the currents ,

L s the length o the wire,

d is the distqance between these two wires

if current are in same directiion, there exists , they exert attractive force on each other

and if currents are in opposite direction, they exert repulsive force

so here we apply

F/L = 4pie-7 * 1900* 1900*0.5 /(2pi * 0.8)

F/L = 0.4512 N

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