*** I am aware that the top of the graph says it is plotting current vs time, th

Question

*** I am aware that the top of the graph says it is plotting current vs time, this is a typo, the graph is capacitor voltage vs time as shown by graph labels****

a) Write the expression for the capacitor's current i(t) over the interval 20 ms <=t< 40 ms, as a function of t.

b) Find the current i(t) flowing through the capacitor at time t = 15 ms.

c) Find the energy stored in the capacitor at t = 30 ms.

The current through a capacitor with capacitance C = 16muF is plotted versus time below. On the plot X = 13V . The capacitor's voltage is 0 for t

Explanation / Answer

a)

i(t) = C*d(Vc(t))/dt

i(t) = -16*10^(-6)*10^(3)*13/20

= -10.4 mA

b) i(15) = 10.4 mA

c)

energy stored = 0.5*C*V*V

= 0.5*16*10^(-6)*6.5*6.5

= 0.338 mJ

Related Questions

Navigate

• Browse (All)
• Browse #
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.