Water flows through a horizontal pipe. The nozzle inlet has a cross sectional ar

Question

Water flows through a horizontal pipe. The nozzle inlet has a cross sectional area (Ain) of 300mm2; the nozzle outlet has a cross sectional area (Aout) of 50mm2. The inlet velocity is 5 m/s. Calculate the mass flow rate (Q) the inlet pressure (Pin). Assume that there are no energy losses and that the pressure (Pout) at the point of exit from the outlet of the nozzle is zero..

Hints:

1)    Use Bernoullis equation and eliminate relevant terms (the pipe is horizontal so there is no height difference i.e. h1=h2 and hence no potential energy change)

2)    For continuity V(in) A(in) = V(out) A(out). We can omit the density term from the Continuity equation since it will remain the same on both sides of the equation

Explanation / Answer

we know that

A1 x v1 = A2 x v2

or v2 = (A1 x v1/A2)

where A1 = 300 mm^2,v1 = 5 m/s and A2 = 50 mm^2

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