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i think i need to break the problem up into its x and y compenets as well as the

ID: 2995051 • Letter: I

Question



i think i need to break the problem up into its x and y compenets as well as the moments that are formed about point B but im having trouble getting started

In this setup, the plane model is rigidly attached to a bent metal rod at its center of gravity G. The other end of the rod is attached to a stage at point B via a pin joint. There are two springs which provide resistance: One linear spring and one torsional spring at point B. These springs are attached to position sensors that determine the deflections in them. The linear spring deflection is Delta and the torsional deflection at B is . Assuming that both springs have zero deflection (Delta = 0 and = 0degree) when there is no airflow, determine the vertical lift force FL and the horizontal drag force FD acting on the airplane at an instant when the sensors show Delta = 3 mm and = 2degree. You can assume drag and lift forces are acting at the center of gravity which is labeled on the figure as G. Take the spring stiffnesses as k = 0.10 N/mm and k- = 45 Nm rad

Explanation / Answer

ill give u the start


one thing u have to understand in this setup is that we are trying to measure lift and drag forces with springs as senor


hense the change in lift drag quantities will directly proprtional to our spring forces


now lets start with torsional spring


im writing all the values directly after calculating


new X=x+delta = 700 + 3 =703 mm

new Y=703*tan(tan^-1(420/700) + 2 ) = 455.9 mm


torque = Kt * phi = F(l) * 703 mm + F(d) * (455.9)


where Kt=45 Nm/rad


linear force = K * delta = F(d)*Cos(2) + F(l)sin(2)


K=0.1N/m


two equations & two unknowns now i dont think its difficult for u too plug in and clculate F(l) = lift force and F(d) = drag force