Academic Integrity: tutoring, explanations, and feedback — we don’t complete graded work or submit on a student’s behalf.

This uses the book (Machines and Mechanisms Applied Kinematic Analysis 4th Editi

ID: 2995547 • Letter: T

Question

This uses the book (Machines and Mechanisms Applied Kinematic Analysis 4th Edition). I will rate for good answers.

Fort part (a)-(d) please give both the magnitude and direction of acceleration with respect to horizontal) The above link is rotating counter-clockwise at a rate of 100 rpm, and accelerating at 200 rad/s2. Determine the total linear acceleration of points A and B. Use gamma = 50 degree and beta = 60 degree . The above link is rotating counter-clockwise at a rate of 200 rpm, and decelerating at 400 rad/s2. Determine the total linear acceleration of points A and B. Use gamma = 50 degree and beta = 60 degree . The above link is rotating counter-clockwise at a constant rate of 50 rpm. Determine the total linear acceleration of points A and B. Use gamma = 50 degree and beta = 60 degree ., For part (c), what would be the total linear acceleration at the center point between A and B?

Explanation / Answer

part1)

Let Aa and Ab are the radial accelertion of point A and B

then

Aa/ra=radial accn=200 rad/s^2

ra=4mm

so Aa=800mm/s^2 = 0.8m/s^2 is perpendicular to the line joining cetre to A ie (270-beta=210) with +ve X axis

lly

for Ab=rb*alpha

rb=900mm

so Ab=1800mm/s^2 = 1.8m/s^2 is perpendicular to the line joining cetre to B ie (270-beta-gamma=160) with +ve X axis

part 2)

Let Aa and Ab are the radial accelertion of point A and B

then

Aa/ra=radial accn=-400 rad/s^2

ra=4mm

so Aa=-1600mm/s^2 = -1.6m/s^2 is perpendicular to the line joining cetre to A ie (270-beta=210) with +ve X axis

lly

for Ab=rb*alpha

rb=900mm

so Ab=-3600mm/s^2 = -3.6m/s^2 is perpendicular to the line joining cetre to B ie (270-beta-gamma=160) with +ve X axis

part c

Let Aa and Ab are the radial accelertion of point A and B

then

Aa/ra=radial accn=000 rad/s^2

ra=4mm

so Aa=000mm/s^2 = 0.0m/s^2 is perpendicular to the line joining cetre to A ie (270-beta=210) with +ve X axis

lly

for Ab=rb*alpha

rb=900mm

so Ab=000mm/s^2 = 0m/s^2 is perpendicular to the line joining cetre to B ie (270-beta-gamma=160) with +ve X axis

partd)

accn of the central point=av of accn of A and B

=0.0/2+0.0/2=0 m/s^2

Hire Me For All Your Tutoring Needs
Integrity-first tutoring: clear explanations, guidance, and feedback.
Drop an Email at
drjack9650@gmail.com
Chat Now And Get Quote