A garden hose is open at one end and capped closed at the other. A swimmer in an

Question

A garden hose is open at one end and capped closed at the other.   A swimmer in an above-ground pool fills the hose with pool water, then throws the capped end out of the pool. The open end of the hose sits at the bottom of the pool, and the capped end sits on the ground just outside the pool and level to the bottom of it.   The external pressure is 1.0 atm. The water in the pool is 2.5 feet deep, and the rim of the pool is 3.5 feet above the ground. What is the water pressure in the capped end of the hose? What is the water pressure at the maximum height of the hose? You can assume that there are no air bubbles in the hose. (Hint: The correct answers are not 1 atm.)

Note: If the cap is removed, water will flow out of the hose, and can eventually drain the pool. (This is called siphoning.)   Later this term, we will see how to calculate the water flow rate.

Explanation / Answer

The pressure at the capped end is (h*roe*gg+Patm)where h is 2.5feet ..pressure is same at same horizontal points.

The pressure at the highest point is (Patm - h*roe*g) where h=3.5-2.5= 1foot.. It will be 3.5*roe*g lesser that the previous one .. Since it is situated 3.5 ft vertically above the capped end.

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