VERIFIED******************PART 1 out of 1 or PART a IS 17.23 Meters ************

Question

VERIFIED******************PART 1 out of 1 or PART a IS 17.23 Meters ***********************************************

WHAT IS PART 2 out of 2 (B) DMAX= ????*****************

An oscillating garden sprinkler which discharges water with an initial velocity v0 of 7 m/s is used to water a vegetable garden. Determine the distance d to the farthest point B that will be watered and the corresponding angle alpha when (a) the vegetables are just beginning to grow, (b) the height h of the corn is 1.8 m. dmax = dmax =

Explanation / Answer

(a)For maximum d lpha=45 degree

So range=u^2/g

=169/9.81 =17.23 m

(b) When h=1.8 m

Considering the first plant we have horizontal distance=2 m

2=ucosp*t

t=2/13cosp

u=initial velocity=13 m/s

p=angle of projection w.r.t x-axis.

and 1.8=usinp t-0.5gt^2

1.8=13sinp*2/13cosp - 0.5*g*4/169cos^2p

Solving for p,we get p=86.6 degree.

d=u^2sin173.2/9.81 =2.039 m

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