The rear wheel drive vehicle shown below weighs 1500 lbs, has a wheelbase of 100
ID: 2997365 • Letter: T
Question
The rear wheel drive vehicle shown below weighs 1500 lbs, has a wheelbase of 100 inches and CG height of 10 inches. It is able to achieve lg forward acceleration. The tires are the same as in Q.1. How much load is transferred from front to rear under this acceleration? The plot below shows the amount of forward acceleration force available per tire as a function of vertical tire load. If the load was initially 550 lbs on the front wheels and 950 lbs on the rear and equally distributed left to right, how much was the total traction force increased due to load transfer? Verify that based on your calculations the vehicle is capable of approximately lg acceleration as indicated in the problem statement.Explanation / Answer
(A)
Wheel Base(L) = 100 in
CG height (h)= 10 in
Weight of Vehicle (W) = 1500 lb
Acceleration = g = 32.2 ft/s2
Load transfer to rear = m*g*(h/L) = W*(h/L) = 1500*(10/100) = 150 lb
(B)
Initial Load per Front Tire = 550/2 = 275 lb
Initial Load per Rear Tire = 950/2 = 475 lb
Traction Load for 475 lb (from curve) = 675 lb
Initial Traction = 2*(675) = 1350 lb
Final Load per Front Tire = (550-100)/2 = 225 lb
Final Load per Rear Tire = (950+100)/2 = 525 lb
Traction Load for 525 lb (from curve) = 725 lb
Final Traction = 2*(725) = 1450 lb
Increased Traction due to load transfer = 1450 - 1350 = 100 lb
(C)
No, the vehicle is not capable of handling 'g' acceleration. the increased traction force is not sufficient to handle the weight tansfer.
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