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S= h[theta /beta - 1/2pi sin(2pi theta /beta)] ds/d theta h [1/beta - cos(2pi th

ID: 2997546 • Letter: S

Question

S= h[theta /beta - 1/2pi sin(2pi theta /beta)] ds/d theta h [1/beta - cos(2pi theta /beta)/beta] d2s/d theta 2 = h2pisin(2pi theta /beta)/beta2 d3s/d theta 3 = h4pi2 cos(2pi theta /beta)/beta3 s = h[35(theta /beta)4- 84(theta /beta)5 + 70(theta /beta)6 -20 (theta /beta)7] ds/d theta = h[14003/beta4 - 42004/beta5 + 42005/beta6 - 140 theta 6/beta7] d2s/d theta = h[42002/beta4 - 168003/beta5 + 2100 theta 4/beta6 - 840 theta 5/beta7] d3s/d theta 3 = h[840 theta /beta4 - 5040 theta 2/beta5 + 8400 theta 3/beta6 - 4200 theta 4/beta7]

Explanation / Answer

yes it is correct.

Used excel to check second one.

140 420 840 420 1680 5040 420 2100 8400 140 840 4200