Tank A is rapidly half -tilled with volatile hydrocarbon. Tank B is 10 times as

Question

Tank A is rapidly half -tilled with volatile hydrocarbon. Tank B is 10 times as large and rapidly filled with the same hydrocarbon. Initially the gas space can be considered to be organic and at the same pressure. The tanks are then closed. The tanks warm 20 degree and the pressure in both tanks goes up. After warming, does one tank have a higher pressure than the other, or are the final pressures the same? Show your result with equations. Your answer should be general; it should not depend on numerical calculations.

Explanation / Answer

Yes the pressure in Tank B is equal of Tank A.
we know that P*V=n*R*T,
where, P- Pressure, V- Volume, n -Number of Moles of gas, R- Constant, T- Temperature.
Initially both the tanks have same pressure, this implies that mole ratio nA/nB = 1/10,
VA/VB = 10.

From, (PA*VA)/(nA*TA) = (PB*VB)/(nB*TB)

Final temperatures are same. Hence the Pressure in the tanks must be same after warming.

Related Questions

Navigate

• Browse (All)
• Browse T
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.