The block of mass m = 10 kg travels from A to B on a flat surface, from B to C o
ID: 2998539 • Letter: T
Question
The block of mass m = 10 kg travels from A to B on a flat surface, from B to C on a cylindrical surface of radius R = 30 m, and at point C it separates from the surface becoming a projectile, finally hitting the ground at point D. All surfaces are smooth. What is the velocity of B so that is seperates from the surface just after passing B and the tangential acceleration at B? What is the noral force applied by the surface on m at C (in Neutons)? Please explain!!!
The block of mass m = 10 kg travels from A to B on a flat surface, from B to C on a cylindrical surface of radius R = 30 m, and at point C it separates from the surface becoming a projectile, finally hitting the ground at point D. All surfaces are smooth. What is the velocity of B so that is seperates from the surface just after passing B and the tangential acceleration at B? What is the noral force applied by the surface on m at C (in Neutons)?Explanation / Answer
If it seperates at B, i.e at point B ,Mass m is loosing contact with surface
Since it is loosing contact,The normal reaction applied by surface on the body is zero.
Actually if it doesn't loose contact with the surface at B,It moves in circular motion along the surface.
So in the limiting case, centrifugal fore is equal to mass of the object at point C since there is no contact.
Centrifugal force = m v2 / r ;
m = mass ,v= velocity , r is radius of curvature.
equating centrifugal force and gravitational force,
v2 / r = g ;
v = sqrt (r g);
v = sqrt (30 * 9.81);
v = 17.15 m/s.
Tangential acceleration is zero since there is no force actiong in horizontal direction (which is tangential direction to maa at point B)
Wherever mass looses contact with surface,total force applied by surface on mass,(Normal reaction) is zero.
So,force applied by surface on mass at C is "Zero".
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