Determine if the following series converge or diverge. Show all work and explain
ID: 3003182 • Letter: D
Question
Determine if the following series converge or diverge. Show all work and explain the reasoning for your determination (what test did you use, Root, Ratio..etc)
Explanation / Answer
c) Just use limit comparison with 1/n^(3/2). You'll get 1 as the limit so the series will converge. d) Use limit comparison with 1/n. You'll get 1 as the limit so the series diverges. e) Since ln(n) 3, then 1/ln(n) > 1/n. We know that the series of 1/n diverges, then the series 1/ln(n) diverges because it's greater than something that diverges (comparison test) f) Use Root Test. You'll get 2/3 as the limit, which is less than 1. So the series converges. g) Using Ratio Test, we get the lim of (2^(2(n+1)) / (2(n+1)+1)!) * ((2n+1)! / (2^(2n))) = (2^(2n+2)) / (2n+3)!) * ((2n+1)! / (2^(2n))) = 2^2 / ((2n+3)(2n+2)) = 0 Since that's less than 1, then the series converges.Related Questions
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