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Creatine (g) Carbohydrates (g) Taurine (g) Alpha Lipoic Acid (mg) Cost $ Cell-Te

ID: 3007861 • Letter: C

Question

Creatine

(g)

Carbohydrates
(g)

Taurine

(g)

Alpha Lipoic

Acid (mg)

Cost

$

Cell-Tech

(Muscle-Tech)

10

75

2

200

2.20

RiboForce

HP (EAS)

5

15

1

0

1.60

Creatine Transport

(Kaizen)

5

35

1

100

0.60

Pre-Load Creatine

(Optimum)

6

35

1

25

0.50

You are thinking of combining Cell-Tech, RiboForce HP, and Creatine Transport to obtain a 10-day supply that provides at least 80 grams of creatine and at least 10 grams of taurine, but no more than 750 grams of carbohydrates and 1,000 milligrams of alpha lipoic acid. How many servings of each supplement should you combine to meet your specifications for the least cost?

a. State the LP in standard form, defining all variables.

b. Solve the LP with the online solver and attach a printout of the solution at the end of the project. In complete sentences, state your solution to the problem. How many servings of each supplement should you combine to meet your specifications for the least cost?

Part 2a

Suppose you were to combine RiboForce HP, Creatine Transport, and Pre-Load Creatine to obtain a 10-day supply that provides at least 80 grams of creatine and at least 10 grams of taurine, but no more than 600 grams of carbohydrates and 2,000 milligrams of alpha lipoic acid. How many servings of each supplement should you combine to meet your specifications for the least cost?

a. State the new LP in standard form, defining all variables.

b. Solve the new LP with the online solver and attach a printout of the solution at the end of the project. In complete sentences, state your solution to the problem. How many servings of each supplement should you combine to meet your specifications for the least cost?

Creatine

(g)

Carbohydrates
(g)

Taurine

(g)

Alpha Lipoic

Acid (mg)

Cost

$

Cell-Tech

(Muscle-Tech)

10

75

2

200

2.20

RiboForce

HP (EAS)

5

15

1

0

1.60

Creatine Transport

(Kaizen)

5

35

1

100

0.60

Pre-Load Creatine

(Optimum)

6

35

1

25

0.50

Explanation / Answer

Minimize P=2.2x+1.6y+.6z+.5w subject to 10x+5y+5z+6w<=80, 2x+y+z+w<=10, 75x+15y+35z+35w>=7500, 200x+100z+25w>=1000

Tableau #1
x y z w s1 s2 s3 s4 -p
10 5 5 6 1 0 0 0 0 80   
2 1 1 1 0 1 0 0 0 10   
75 15 35 35 0 0 -1 0 0 7500   
200 0 100 25 0 0 0 -1 0 1000   
22 16 6 5 0 0 0 0 10 0

Tableau #2
x y z w s1 s2 s3 s4 -p
0 100 0 95 20 0 0 1 0 600
0 100 0 75 0 100 0 1 0 0
0 120 -20 205 0 0 -8 3 0 57000
200 0 100 25 0 0 0 -1 0 1000   
0 1600 -500 225 0 0 0 11 1000 -11000

Tableau #3
x y z w s1 s2 s3 s4 -p
0 -100 0 0 75 -475 0 -1 0 2250   
0 100 0 75 0 100 0 1 0 0
0 -575 -75 0 0 -1025 -30 1 0 213750
150 -25 75 0 0 -25 0 -1 0 750
0 325 -125 0 0 -75 0 2 250 -2750

Tableau #4
x y z w s1 s2 s3 s4 -p
0 0 0 1 1 -5 0 0 0 30   
0 100 0 75 0 100 0 1 0 0
0 -45 -5 -5 0 -75 -2 0 0 14250
2 1 1 1 0 1 0 0 0 10   
0 5 -5 -6 0 -11 0 0 10 -110   

Part 2a) Minimize P=2.2x+1.6y+.6z+.5w subject to 10x+5y+5z+6w<=80, 2x+y+z+w<=10, 75x+15y+35z+35w>=600, 200x+100z+25w>=2000

Tableau #1
x y z w s1 s2 s3 s4 -p
10 5 5 6 1 0 0 0 0 80   
2 1 1 1 0 1 0 0 0 10   
75 15 35 35 0 0 -1 0 0 600
200 0 100 25 0 0 0 -1 0 2000   
22 16 6 5 0 0 0 0 10 0

Tableau #2
x y z w s1 s2 s3 s4 -p
0 0 0 1 1 -5 0 0 0 30   
2 1 1 1 0 1 0 0 0 10   
0 -45 -5 -5 0 -75 -2 0 0 450
0 -100 0 -75 0 -100 0 -1 0 1000   
0 5 -5 -6 0 -11 0 0 10 -110

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