A blackjack is when 2 cards are dealt and one is an Ace and the other is either

Question

A blackjack is when 2 cards are dealt and one is an Ace and the other is either a 10, Jack, Queen, or King. How many possible ways are there to deal a blackjack? Suppose four balls are drawn at the same time at random from a box containing 4 red balls and 6 white balls. What is the probability of drawing no red balls? What is the probability of drawing 1 red ball and 3 white balls? What is the probability of drawing at least 1 red ball? What is the probability of drawing at most 1 red ball? Suppose that there are 6 people in a room. What is the probability that at least 2 are born in the same month? You may assume that each person's month is equally likely to be any of the 12 months in a year. Suppose we flip 3 coins and observe the outcomes. Write the sample space. What is the probability of getting 3 heads? What is the probability of getting 3 heads given that there is at least one head? What is the probability of getting 3 heads given that there is at least two heads? A spam filter is designed by looking at commonly occurring phrases in spam. Suppose that 80% of email is spam. In 10% of the spam emails, the phrase "free money" is used, whereas this phrase is only used in 1% of non-spam emails. A new email has just arrived, which does mention "free money". What is the probability that it is spam? Consider a standard 52 card deck. What is the probability of being dealt a king of hearts and then being dealt the ace of hearts, if the cards are not returned to the deck? Suppose two events are mutually exclusive. Does this imply they are independent? Explain. Is it possible for an event to be independent of itself? If so, when is this the case? Prove that if A and B are independent, then A and B' are independent. First prove that P(B|A) + P(B'|A) = 1 Then prove P(B|A) = P{B) implies P{B'|A) -= P(B')

Explanation / Answer

1.

probabilty of getting an ace = 4/52 = 1/13

probability of getting an 10, jack, queen and king = 16/51

Probabilty = 2*(1/13)*(16/51) = 0.04826

multiply by 2, because there is 2 cases:one is ace first and other is when ace draws second time.

Related Questions

Navigate

• Browse (All)
• Browse A
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.