A hollow steel ball weighing 4 pounds is suspended from a spring. This stretches

Question

A hollow steel ball weighing 4 pounds is suspended from a spring. This stretches the spring 1/4 feet. The ball is started in motion from the equilibrium position with a downward velocity of 2 feet per second. The air resistance (in pounds) of the moving ball numerically equals 4 times its velocity (in feet per second). Suppose that after t seconds the ball is y feet below its rest position. Find y in terms of t. (Note that the positive direction is down.) Take as the gravitational acceleration 32 feet per second per second. y =

Explanation / Answer

Here the meaning of saying that it has 1 kilogram of mass and therefore weigth 9.8 newtons means that

using the formula that F= mg, when m= 1 kilogram and g = 9.8 m/sec^2 ,

we have its weight as 1 x 9.8 kg-m/sec^2 that means that the total force that is on the surface of the earth would have a force of 9.8 Newton and thus its weight will be 9.8 newton.

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