Please show all work step by step!! Please don\'t just give me answers.Thank you

Question

Please show all work step by step!! Please don't just give me answers.Thank you.

In whales, the gene controlling tail shape exists as a dominant notched (T) or a recessive smooth (t) allelic form. A separate gene controls whether there are white markings on the dorsal fin or not. The dominant allele of the second gene (W) results in no white markings whereas the other allele (w) results in white markings in individuals homozygous for the recessive allele. The T and W genes are linked together and are 20 map units apart. A purebreeding female with a notched tail and white markings on her dorsal fin mates with a purebreeding male with a smooth tail and no white markings on his dorsal fin. One of the F1 females resulting from this cross mates with a homozygous recessive male.

-Draw out the genotypes of the parents of the original cross on chromosomes (the purebreeding parents)

-Draw out the genotypes of the F1 heterozygote female resulting from the cross in part a and the homozygous recessive male (you do not need to include the sex chromosomes).

-What proportion (%) of the progeny from the cross in (b) would express each of the following phenotypes?

Notched tail, white markings on dorsal fin _____________

Notched tail, no white markings on dorsal fin _____________

Smooth tail, white markings on dorsal fin _____________

Smooth tail, no white markings on dorsal fin _____________

Explanation / Answer

The female parent is TTww and the male parent is ttWW

Now by crosiing these two , we get all the progeny to be of TtwW, That means all the progeny will have notched and with no white marks .

This is the F1 progeny .

When one of the female of this F1 generation(TtWw) is crossed with a homozygous recessive male (ttww), we get the following results,

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