Hoping to attract more shoppers a city builds a new public parking garage downto
ID: 3012323 • Letter: H
Question
Hoping to attract more shoppers a city builds a new public parking garage downtown. The city plans to pay for the structure through parking fees. The consultant, Who advised the city on this project, randomly selected 44 weekdays. Daily fees collected averaged $126. Based on data from other parking structure, the consultant will assume parking fees at this parking garage are Normally distributed with a standard deviation of $15. What a 90% confidence interval for the mean daily income this parking garage will generate from the pinking from the parking fees? A) ($107.31. $144 69) B) ($121.57. $130, 43 C) ($122.28. $129.72) D) ($125.44. $126 56) If a 95%. confidence interval constructed instead. how would the margin of error compare to the one used lo create the would confidence interval? A) The margin of error for the 95% confidence interval would be smaller. B) The margin of error for the 95% confidence interval would be the same. The margin of error for the 95% confidence interval would be larger D) This cannot he determined from the information given. In the last mayoral election a large city. 47% of the adults over the age of 65 voted Republican A researcher wishes to determine if the proportion of adults over the age of 65 in the city who plan lo tote Republican in the next mayoral election hat changed Let p represent the proportion of the population of all adults over the age of 65 in the city who plan to vote Republican in the next mayoral election In terms of p, the researcher should test which of the following null and alternative hypotheses? The test statistic for a two-tailed significance test for a population mean a z=- 2.12. What is the corresponding p-value? A) 0.017 B) 0.034 C)0.483 D)0.983Explanation / Answer
n = 44 days
Mean = 126
Standard deviation =15
25) CI is 90%
Z=1.645
CI at 90% = 126+/- 1.645*15/sqrt(44)
122.28 to 129.72
n = 44 days
Mean = 126
Standard deviation =15
25) CI is 90%
Z=1.645
CI at 90% = 126+/- 1.645*15/sqrt(44)
122.28 to 129.72
Answer is C
26)
C) the margin of error for the help 95% confidence interval would be larger
27)
B is the right answer.
Its a 2 tailed test
28)
Z=-2.12
Its a two mailed significance.
P(Z=-2.12) = .0170
Answer is A
Related Questions
Navigate
Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.