How many gallons of a 50% antifreeze solution must be mixed with 100 gallons of

Question

How many gallons of a 50% antifreeze solution must be mixed with 100 gallons of 25% antifreeze to get a mixture that is 80% antifreeze? Use the six-step method

Explanation / Answer

Dear Student Thank you for using Chegg Given we have 100 gallon of 25% antifreeze solution => Solution to mix = 90% Antifreeze Solution Let X gallons of 90% antifreeze solution is added in order to produce 80% antifreeze solution Total Volume of final solution = 100 + X Total antifreeze in final 80% solution (A) = 0.8(100 +X) gallons Quantity of antifreeze added in the initial solution = 0.9X gallons Hence total antifreeze in solution after addition is = 0.9X + 0.25*100 => 0.9X + 0.25*100 = 0.8(100 +X) 0.1X = 55 X = 550 x = 550 gallons Solution

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