I need help with questions 4b and 4c below the graph I completed: thnk the alfer

Question

I need help with questions 4b and 4c below the graph I completed:

thnk the alfermahve 1s sin 3) as areaprocal snce thai's what the graphing command recogmzcd. I thought Tdad somelhing wrong at hrst x-pi/2), but it seems it simplified the equation on its own. Graph the functions on the same axes. Include a legend. Let plot begin at x--2 and end at x . Also, be sure to indude the plotting Sample code for discont=true (click on the triangle to open) plot(tan(x), tan(0.25 x), 0.25 tan(x)], x= 2 Pi Pi, legend [tan(x), ta (0 25 x), 0.25 tan(x)], disco true) -2 -10 -15 20 tan(x) tan( 0.25x)--025 tan -- Maple Default Profle c:Users Kate Deskta

Explanation / Answer

Solution:

a)

a(x) = tanx

as we know;

period of tanx is .

Note - remember the periods of basic trignometric usables(like sinx,cosx,tanx,cotx etc.)

b)

b(x) = tan(0.25 x)

as we know the period of tan(ax) can be defined as;

period of tanx / coffiecient of angle

=> period of b(x) = /0.25

=> period of b(x) = 4

c / 4c)

c(x) = 0.25 tan(x)

Here there's no difference in the period of the c(x) and tanx because coeffiecient of angle that tangent holds is still same.

=> period of c(x) = .

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