Find the area of the sector of the circle with radius 2 centimeters and central

Question

Find the area of the sector of the circle with radius 2 centimeters and central angle 10 pi/6. a. A = 5 pi/13 cm^2 b. A = 100 pi/3 cm^2 c. A = 10 pi/3 cm^2 d. A = 5 pi/2 cm^2 e. A = 20 pi/3 cm^2 The displacement from equilibrium of an oscillating weight suspended by a spring is given by y(t) = 3cos 10, where y is the displacement in centimeters and t is the time in seconds. Find the displacement when t = 0.65, rounding answer to four decimal places. a. -3.7018 cm b.-6.4350 cm c. 23.8825 cm d. 2.9298 cm e. -1.6362 cm Evaluate each function. Round your answers to four decimal places. cot(pi/15) and tan pi/15 a. 4.7046 and 0.2126 b. 4.7546 and 0.2626 c. 4.8546 and 0.3626 d. 4.8046 and 0.3126 e. 4.9046 and 0.4126

Explanation / Answer

Solution:

The area of a sector of a circle is ½ r²

where r is the radius and the angle in radians subtended by the arc at the center of the circle.

hence, the area of the sector,A = ½.(2)2(10pi/6)

=> the area of the sector,A = 10pi/3 cm2

Option-C

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