(1 point) The graph of the function,f(x) = e-r-1 can be obtained from the graph

Question

(1 point) The graph of the function,f(x) = e-r-1 can be obtained from the graph of g(x) er by two of the following actions: (a) reflecting the graph of g(r in the y-axis; (b) reflecting the graph of g(r) in the x-axis; (c) shifting the graph of g(x) to the right 1 units; (d) shifting the graph of g(x) to the left 1 units; (e) shifting the graph of g(x) upward 1 units; (f) shifting the graph of g(r) downward 1 units; Your answer: Apply the action (input a, b, c, d, e, or f) then apply the action (please give your answer in the order the changes are applied, e.g. a first, then b second) The range of the function,f(x) is-f(x) > A, find A. The value of A is Is the domain of the function f(x) still (-0o, oo)? Your answer is (input Yes or No)

Explanation / Answer

f(x) =e-x-1

Because of -x that is a - sihn inside the function, reflection is across y axis.

So for first blank, correct option is a.

And because of -1 with functiin, the graph shifts 1 unit down.

So for second blank, correct option is f.

Range of f(x)=

f(x)>-1 , since the asymptote is at -1

so A=-1

And yes the domain is still (-infinity,infinity), since there is no restriction on x.

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