B.) Would this concern a medical professional? Explain. C.) Find the equation of
ID: 3018433 • Letter: B
Question
B.) Would this concern a medical professional? Explain.
C.) Find the equation of the horizontal asymptote. What does this mean in this context?
D.) Find all of the intercepts of C and interpret their meaning in the context of this problem.
E.) How many hours after injection does a maximum concentration of the drug occur in the bloodstream? Round answer to nearest hundredth.
F.) Suppose you need to re-administer this injection at the point when the concentration is less than 0.5%. If the first injection was given at 8:00 am, what time should the next injection be given?
h3+8Explanation / Answer
given C(h)=(2h2+5h)/(h3+8)
=>C(h)=h(2h+5)/(h3+23)
=>C(h)=h(2h+5)/((h+2)(h2-2h+4))
a)
for vertical asymptote denominator =0
=>(h+2)(h2-2h+4)=0
=>h+2=0
=>h=-2
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B)
this Wouldnot concern a medical professional. since h is negative. actually time is always positive.
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C)
horizontal symptote ,y= lim[h->] C(h)
=>y=lim[h->](2h2+5h)/(h3+8)
=>y=lim[h->]h2(2+(5/h))/(h3(1+(8/h3)))
=>y=lim[h->](2+(5/h))/(h(1+(8/h3)))
=>y=0
horizontal asymptote is y=0
after a long time concentration of medicine in bloodstream nears zero percent
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D)
for horizontal intercept , C(h)=0
=>(2h2+5h)/(h3+8)=0
=>(2h2+5h)=0
=>h(2h+5)=0
=>h=0, h=-2.5
h=0 => concentration of medicine in bloodstream is zero when h=0. h=-2.5 has no significance
for vertical intercept , C(0)=(2*02+5*0)/(03+8)
=>C(0)=0
initial concentration of medicine in bloodstream is zero
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E)
C(h)=(2h2+5h)/(h3+8)
C'(h)=-2(h4+5h3-16h-20)/(h3+8)2
for local extremum , C'(h)=0
=>-2(h4+5h3-16h-20)/(h3+8)2=0
=>h=-4.41, h=1.95
h=-4.41 has no significance
maximum concentration of the drug occur in the bloodstream after 1.95 hours
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F)
C(h)=(2h2+5h)/(h3+8)=0.5
=>(2h2+5h)=0.5(h3+8)
=>(4h2+10h)=(h3+8)
=>h3-4h2-10h+8=0
=>h=0.65607,5.5436
injection given at h=0,i.e, 8:00am
cocentration will be less than 0.5% after 5.5436 hours
=>injection should be given at 8+5+(60*.5436)
=>injection should be given at 13:33
=>injection should be given at 1:33 pm
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