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::: Apps iPhone Upgrade Pro MARIA A POLANCO WGTC-Blackboard L » Other book Precalculus Fall 2017-21702 Quiz: Quiz 7: 6.1 6.2 6.3 Time Remaining: 01:07:14 Submit This Question: 1 pt 2 of 15 (1 complete) This Quiz: 15 pts po: To find the distance from the house at A to the house at B, a surveyor measures the angle ACB, which is found to be 30° and then walks off the distance to each house, 50 feet and 60 feet, respectively. How far apart are the houses? A. 60 ft 50 ft 30° The houses arefeet apat n as needed) (Round to the nearest hundredth as needed.)

Explanation / Answer

Let the houses are x feet apart.

Using cosine law

x2=502+602-2(50)(60) cos 30

x2= 6100 -6000 cos 30

x=30.06 feet

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