A random sample of n = 4 scores is obtained from a normal population with m=20 a

Question

A random sample of n = 4 scores is obtained from a normal population with m=20 and theta=4. what is the probability of obtaining a mean greater than M=22 for this sample? A. 1.00 B. 0.3085 C. 0.1587 D. 0.50
Please explain ty A random sample of n = 4 scores is obtained from a normal population with m=20 and theta=4. what is the probability of obtaining a mean greater than M=22 for this sample? A. 1.00 B. 0.3085 C. 0.1587 D. 0.50
Please explain ty A random sample of n = 4 scores is obtained from a normal population with m=20 and theta=4. what is the probability of obtaining a mean greater than M=22 for this sample? A. 1.00 B. 0.3085 C. 0.1587 D. 0.50
Please explain ty

Explanation / Answer

z = (X-Mean)/(S.D/sqrt n)
z = (22-20)/(4/sqrt 4) = 1

1-0.8413=0.1587

Letter C

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