Suppose that the average number of burgers given in front of a store is three pe

Question

Suppose that the average number of burgers given in front of a store is three per day.

(a) Estimate the probability, p, that at leastv5 parking tickets will be given out in front. (What inequality are you using?)

(b) Assume now (for parts (b), (c), and (d)) that you are told that the variance of the number of burgers in any one day is 9. Now give an estimate of p that takes advantage of knowing the variance (using an inequality).

(c) Give a Central Limit Theorem estimate for the probability q that in the month of December (which has 31 days, and we consider each day to be like any other day) there are more than 75 burgers given out.

(d) Use an inequality to get the best bounds you can on the probability q estimated in part (c).

Explanation / Answer

a) at least 5 parking tickets

P = 3 /5 + 4 /5 + 5/5 = 2.4 / 5 = 0.48

b)

using chev inequaltiy

var = 9

9 = 1 / p^2

p = 1/3

for the other literals I can gladly help you but you should post it in a new question

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