Suppose that among all adults in the US, 23.9% are Catholic, what is the probabi
ID: 3020892 • Letter: S
Question
Suppose that among all adults in the US, 23.9% are Catholic, what is the probability that a randomly selected US. adult is not Catholic? Don't give your answer as a percent. 2) 3) An upscale restaurant offers a special fixed price menu in which, for a fixed dinner cost, a diner can select from six appetizers, four salads, five entrees, and three desserts. How many different dinners are available if a dinner consists of one appetizer, one salad, one entree, and one dessert? 4) How many different four-digit passcodes (like 5505) can be formed if the first digit can only be from 1 through 9, while the other three digits can be from 0 through 9, and the digits cannot repeat? Five cards are dealt from a standard 52-card deck. What is the probability that 2 jacks and 3 queens are drawn? Give your answer in the form: 1, where n is a whole number. 5)Explanation / Answer
2) SEE THE PERCENTAGE IS ALSO A SYMBOLIC REPRSENTATION FOR THE PROBABILITY,
HERE THE 23.9% ARE CATHOLIC WHICH MEANS THAT OF THE TOTAL POPULATION 23.9% WILL BE CATHOLIC
HENCE THE CHANCES OF ANY RANDOM PERSON BEING CATHOLIC = 0.239
SO PERSON SELECTED BEING NON CATHOLIC = 1- 0.239 = 0.761
AS PERCENTAGE ALSO REPRESENTS THE CHANCE.
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