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I Just need help with just #4!!!!!!!!!!!!!! Answer for the #4 is 28 percent, But

ID: 302106 • Letter: I

Question

I Just need help with just #4!!!!!!!!!!!!!! Answer for the #4 is 28 percent, But I don't know how to get there, I need an clear explanation Please!!!!!!!

FOr number #3 Answers are

NEE for the tropical pasture is - 262 g C/m2/year, and negative sign indicates that it is source for CO2.

2,345 g C/m/year - 2,606 g C/m2/year= - 262 g C/m2/year

NEE For the second-growth forest is 442 C/m2/year, and the value being positive indicates that it is acting as Sink.

2,082 g C/m2/year - 1,640 C/m2/year= 442 C/m2/year

#4 Reduce the both value to half, and you get

0.5 (- 262 g C/m2/year) + 0.5 (442 g C/m2/ year) = 90 g C/m2/year

(442 C/m2/year- 90 g C/m2/year)/( 442 C/m2/year)=80% C/m2/year

which is This is an 80% reduction in NEE by tropical rainforests,

I need the steps for get to 28% reduction in C uptake by the terrestrial land surface.!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!

Explanation / Answer

3rd part

NEE for tropical pasturee = 2345-2606

= -261g C/m2/year

NEE For the second-growth forest is 442 C/m2/year, and the value being positive indicates that it is acting as Sink.

2,082 g C/m2/year - 1,640 C/m2/year= 442 C/m2/year

4th part

reduce both values to half

=0.5 (- 261g C/m2/year) + 0.5 (442 g C/m2/ year) =-130g C/m2/year+221g C/m2/year

= 90g C/m2/year

now

as the production will be decreased to half if half of tropical forests are converted into pastures

(.5*442 C/m2/year- 90 g C/m2/year)/( 442 C/m2/year)=(221 C/m2/year- 90 g C/m2/year)/( 442 C/m2/year)

= 131/442

=0.296 * 100

29.6%

so approximately in round figure we may say 28 % depending on the values