Problem #4 please. 1. When a car is brought to a local garage for service, it ha

Question

Problem #4 please.

1. When a car is brought to a local garage for service, it has a 52% chance of getting an oil change; 29% of new transmission fluid; antifreeze flush; 15% will have new transmission fluid and an antifreeze flush; 11% will have new transmission fluid and oil; 16% will have an antifreeze flush and an oil change; and 7% will have all three done. (a) Find the probability of having only an oil change. (b) Find the probability of just new transmission fluid. (c) Find the probability of some other type of service being done. 2. A sample of 1000 college students showed that 770 have a Facebook account, 700 have a Twitter account, 370 have a LinkedIn account, 540 have both Facebook and Twitter, 300 have Twitter and LinkedIn, 280 have Facebook and LinkedIn, and 230 have all three. If a student is selected at random, find the probability that (a) The student has Facebook and/or Twitter but not LinkedIn (b) The student has just LinkedIn. (c) The student does not have one of these accounts 3. Skippy needs a ride to the airport and has only two friends who have cars, Buffy and Jody. The probability that Buffy is unavailable is 0.25, the probability that Jody is unavailable is 0.35, and the probability that both are unavailable is 0.15. Find the probability that (a) both Buffy and Jody are available; (b) at least one of them is available. 4. A student applied for an SMU Alumni Association scholarship and a scholarship from the local Rotary. The student has a probability of 0.27 of receiving the Alumni scholarship, a probability of 0.16 of receiving the Rotary scholarship, and a probability of 0.32 of winning either or both scholarships. Find the probability that the student: (a) wins both scholarships (b) wins neither scholarship (c) wins just the Alumni scholarship.

Explanation / Answer

4.

Let

A = alumini scholarship
R = rotary scholarship

a)

P(A n R) = P(A) + P(R) - P(A U R)

= 0.27 + 0.16 - 0.32 = 0.11 [ANSWER]

**************

b)

P(A U R)' = 1 - P(A U R) = 1 - 0.32 = 0.68 [ANSWER]

*************

c)

P(A only) = P(A) - P(A n R) = 0.27 - 0.11 = 0.16 [ANSWER]

Related Questions

Navigate

• Browse (All)
• Browse P
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.